@[email protected]M to Science [email protected]English • 9 days agoSo muchmander.xyzimagemessage-square18fedilinkarrow-up1333arrow-down15
arrow-up1328arrow-down1imageSo muchmander.xyz@[email protected]M to Science [email protected]English • 9 days agomessage-square18fedilink
minus-square@emergencyfoodlinkEnglish0•9 days agoNot a mathematician, but I’m pretty sure this isn’t necessarily true. What if L is -1 and f(x) = x^2? Also I think your function has to be continuous.
minus-square@[email protected]linkfedilinkEnglish3•edit-28 days agoYou’re right on all three counts. It’s not always true, f(x0) has to be L, and the function has to be continuous.
Not a mathematician, but I’m pretty sure this isn’t necessarily true. What if L is -1 and f(x) = x^2? Also I think your function has to be continuous.
You’re right on all three counts. It’s not always true, f(x0) has to be L, and the function has to be continuous.