Sayori Drake
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  • quantenzitrone@feddit.de
    7·
    8 months ago

    since gender is not binary, trans is not a binary operation

    so double trans [ interpreted as trans²: x ↦ trans(trans(x)) ] is not necessarily the identity funcion [ id: x↦x ]

    • FuctangleOP
      4·
      8 months ago

      Any gender is necessarily an identity function, checkmate (I’m not numerate)