Sjmarf to Math Memes@lemmy.blahaj.zoneEnglish · 7 days agoSimplifyimagemessage-square42fedilinkarrow-up1330arrow-down111
arrow-up1319arrow-down1imageSimplifySjmarf to Math Memes@lemmy.blahaj.zoneEnglish · 7 days agomessage-square42fedilink
minus-squareLostXOR@fedia.iolinkfedilinkarrow-up46·6 days agoFun fact, omitting the (x-x) zero term and expanding the entire polynomial, you’d get something with 2^25 = 33,554,432 terms. May be slightly excessive!
minus-squarethreelonmusketeerslinkfedilinkEnglisharrow-up8·6 days agoCouldn’t you combine a lot of like terms as you went along, though? A polynomial of the order x26 would only have 27 terms.
minus-squareLostXOR@fedia.iolinkfedilinkarrow-up2·6 days agoNo, because each coefficient is its own variable; they’re not constants.
minus-squarethreelonmusketeerslinkfedilinkEnglisharrow-up1·edit-25 days agoHuh, I’m so used to polynomials being in the form ax^2 + bx + c that I never considered that every letter might be a variable.
Fun fact, omitting the (x-x) zero term and expanding the entire polynomial, you’d get something with 2^25 = 33,554,432 terms. May be slightly excessive!
Couldn’t you combine a lot of like terms as you went along, though? A polynomial of the order x26 would only have 27 terms.
No, because each coefficient is its own variable; they’re not constants.
Huh, I’m so used to polynomials being in the form ax^2 + bx + c that I never considered that every letter might be a variable.