m_f@midwest.socialM to Fun Loops ▶️@midwest.socialEnglish · 1 day ago[R] Stupidest ways people have solved coding interviewsloops.videoexternal-linkmessage-square33fedilinkarrow-up177arrow-down15
arrow-up172arrow-down1external-link[R] Stupidest ways people have solved coding interviewsloops.videom_f@midwest.socialM to Fun Loops ▶️@midwest.socialEnglish · 1 day agomessage-square33fedilink
minus-squarelobut@lemmy.calinkfedilinkarrow-up11·edit-21 day agoBecause the abs(3) == 3 is true and that isn’t even. An even number of flips would be true and an odd number of flips would be false which works out. I was thinking a bitwise & or converting it to a string and testing if the right most character is 0, 2, 4, 6, 8 would be panic mode solutions too.
minus-squareKraiden@kbin.earthlinkfedilinkarrow-up2·23 hours agoyou might be able to do it with a bitwise op? My track record tonight is not great so I’m not going to comment. Have a look at @ImplyingImplactions comment for a loopless solution
minus-squareUID_Zero@infosec.publinkfedilinkEnglisharrow-up2·20 hours agoBitwise and with 0x1. If result is 0, it’s even. Least significant bit is always 1 for odd numbers.
Because the abs(3) == 3 is true and that isn’t even.
An even number of flips would be true and an odd number of flips would be false which works out.
I was thinking a bitwise & or converting it to a string and testing if the right most character is 0, 2, 4, 6, 8 would be panic mode solutions too.
you might be able to do it with a bitwise op? My track record tonight is not great so I’m not going to comment. Have a look at @ImplyingImplactions comment for a loopless solution
Bitwise and with 0x1. If result is 0, it’s even. Least significant bit is always 1 for odd numbers.