Gollum@feddit.de to Science Memes@mander.xyzEnglish · 1 year agoAre you interested?i.imgur.comimagemessage-square10fedilinkarrow-up1141arrow-down18
arrow-up1133arrow-down1imageAre you interested?i.imgur.comGollum@feddit.de to Science Memes@mander.xyzEnglish · 1 year agomessage-square10fedilink
minus-squareearned_myself_a_gin@reddthat.comlinkfedilinkEnglisharrow-up13·1 year agoCan someone explain this? Integral from 10 to 13 of 2x? It’s been a long time since calculus for me, but isn’t that like 2x² + c or something like that?
minus-squarecamr_on@lemmy.worldlinkfedilinkEnglisharrow-up4·1 year agoNever heard of this before, looks cool. Wish I had that when I was taking calculus lol
minus-squareCelloMike@startrek.websitelinkfedilinkEnglisharrow-up16·1 year agoJust x²+c, but when you’re integrating between limits the +c doesn’t matter - so you’re just left with the difference between 13² and 10²…
minus-squarezigmus64@lemmy.worldlinkfedilinkEnglisharrow-up11·1 year agoThe integral of 2xdx is x^2 + c, and it’s evaluated from 10 to 13. So you’d have the following: (13^2 + c) - (10^2 + c). The c’s cancel. I’ll leave you to do the rest…
Can someone explain this? Integral from 10 to 13 of 2x? It’s been a long time since calculus for me, but isn’t that like 2x² + c or something like that?
Is this Wolfram Alpha?
It is Photomath
Never heard of this before, looks cool. Wish I had that when I was taking calculus lol
Looks like
Just x²+c, but when you’re integrating between limits the +c doesn’t matter - so you’re just left with the difference between 13² and 10²…
The integral of 2xdx is x^2 + c, and it’s evaluated from 10 to 13. So you’d have the following:
(13^2 + c) - (10^2 + c).
The c’s cancel. I’ll leave you to do the rest…
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