0x4E4F@infosec.pub to Programmer Humor@programming.devEnglish · 6 个月前Not my problem sortinfosec.pubimagemessage-square69fedilinkarrow-up1758arrow-down114
arrow-up1744arrow-down1imageNot my problem sortinfosec.pub0x4E4F@infosec.pub to Programmer Humor@programming.devEnglish · 6 个月前message-square69fedilink
minus-squarexmunklinkfedilinkarrow-up97·6 个月前Guaranteed to sort the list in nearly instantaneous time and with absolutely no downsides that are capable of objecting.
minus-squarefrezik@midwest.sociallinkfedilinkarrow-up48·6 个月前You still have to check that it’s sorted, which is O(n). We’ll also assume that destroying the universe takes constant time.
minus-squareBatmanAoD@programming.devlinkfedilinkarrow-up44·6 个月前In the universe where the list is sorted, it doesn’t actually matter how long the destruction takes!
minus-squaregroet@feddit.orglinkfedilinkEnglisharrow-up13·6 个月前It actually takes a few trillion years but its fine because we just stop considering the “failed” universes because they will be gone soon™ anyway.
minus-squareBenjaben@lemmy.worldlinkfedilinkarrow-up9·6 个月前 We’ll also assume that destroying the universe takes constant time. Well yeah just delete the pointer to it!
minus-squarevithigar@lemmy.calinkfedilinkarrow-up16·6 个月前Except you missed a bug in the “check if it’s sorted” code and it ends up destroying every universe.
minus-squaredb2@lemmy.worldlinkfedilinkarrow-up7·6 个月前There’s a bug in it now, that’s why we’re still here.
Guaranteed to sort the list in nearly instantaneous time and with absolutely no downsides that are capable of objecting.
You still have to check that it’s sorted, which is O(n).
We’ll also assume that destroying the universe takes constant time.
In the universe where the list is sorted, it doesn’t actually matter how long the destruction takes!
It actually takes a few trillion years but its fine because we just stop considering the “failed” universes because they will be gone soon™ anyway.
Eh, trillion is a constant
amortized O(0)
Well yeah just delete the pointer to it!
universe.take()Except you missed a bug in the “check if it’s sorted” code and it ends up destroying every universe.
There’s a bug in it now, that’s why we’re still here.
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