I wouldn’t like to actually block a community all together here, but yeah, I would like to see less posts of that community. Is there a way to do this, either in Jerboa or the web UI?

  • 15RedstonesEnglish
    27·
    1 year ago

    Or just “count upvotes from posts from this community as half” when sorting posts by Hot. Maybe calculating the score of a post from both the points and the size of the community so that posts from smaller communities are visible too.

    • Geiger0148English
      13·
      1 year ago

      Weighting by community, so my feed isnt completely overrun by cats and I see enough Norwegian death metal crochet posts

      • b_nEnglish
        41·
        1 year ago

        Feed overrun by cats… What’s the problem?

        • cyanarchyEnglish
          1·
          1 year ago

          As a reddit transplant (aren’t we all?) I’m going to be avoiding cat subreddits entirely. Not that I don’t like them, it just opens the floodgates for me to subscribe to all of them and I’ll be back to square zero.

    • canEnglish
      5·
      1 year ago

      That sounds like a great idea.

      • Trekman10English
        2·
        1 year ago

        Maybe it can get requested on like github or something idk where the devs are contactable

        • canEnglish
          1·
          1 year ago

          They’re on Github but pretty swamped atm.

          At the moment we are urgently working to solve major issues, such as optimizing slow database queries, ripping out the inefficient websocket API, and fixing a major security vulnerability (big thanks to deadcade). In addition we suddenly have to manage dozens of pull requests. To give us time to work on these priorities, it would be very beneficial if users could refrain from interacting with issue trackers when possible. Before opening an issue, make sure that it hasn’t been reported before. And when writing comments, make sure that they actually contribute to solving the issue at hand. Generally it is better to move discussions to Lemmy if possible.