• BlueMagma
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    1 year ago

    Brilliant, now I wonder what ages this works for, I figured only 1 and 2, but then I realised we could write the father’s age in other bases…

    1 = 2^0 (20 b10)

    2 = 2^1 (21 b10)

    3 = 3^1 (31 b7 = 22)

    6 = 6^1 (61 b4 = 25) if they are lucky the grand father will be 61 that year :-D

    8 = 2^3 (23 b12 =27)

    9 = 9^1 (91 b3 = 28)

    14 = 14^1 (141 b4 = 33)

    • aDogCalledSpot@lemmy.zip
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      1 year ago

      You have mistakes in a few of those. The number “61” doesnt exist in b4. 25b10 in b4 is “121”.

      Similar problem with 91b3 and 141b4.

      • BlueMagma
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        1 year ago

        Indeed, I was so focused on the algebraic side I didn’t even think about it :-D

        I was computing 6*4+1=25